Strings & Pointers

Consider the following C code

char str[] = "iCDuLNb";
char *p = str + 1;
printf("%s", p);

if the base address for str is 0x000081e0, what will be printed when the printf statement is executed? Output: "CDuLNb"

Additionally, what is the value of p in hexadecimal? p = 0x000081e1

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Answer

When working with strings in C, remember that strings are null-terminated. This means that the end of a string is marked by the null character ('\0'), which tells functions like printf where to stop printing.

In the given example, the pointer p is initialized as str + 1, meaning it points to the character at position 1 in the string iCDuLNb. The printf("%s", p); statement prints the substring starting from that character until the null character is encountered, giving us the Output seen above.

Meanwhile, to find the address of p, we can calculate it as follows:

1. The base address of str is 0x000081e0.
2. The offset to the character at index 1 is 1 * 1 (since each character is 1 byte).
3. Therefore, the address of p is 0x000081e0 + 1.